TEAM 1 - Assignment
Assignment
1. Determine whether each of the following sentences is a statement.
a) In 1998 William Clinton was the President of the United states. - It is a statement.
b) x+3 is a positive integer.- Not a statement.
c) Fifteen is an even number. - It is a statement.
d) If Jennifer is late for the party, then her cousin Zachary will be quite angry.- It is a statement.
e) What time is it? -Not a statement.
f) As of June 30,1998,Christine Marie Evert had won the French Open seven times.- It is a statement
2) Use truth tables to verify the following logical equivalences
i) p → (q/\r)<==>(p→ q)/\(q→ r)
ii) [(p\/q) → r ] <==>[ ( p→ r ) /\(q→ r)]
iii) [p→ (q\/r)] <==> [¬r→ (p→ q)]
Ans : i)
P | Q | r | q/\r | p→(q/\r) | p→ q | p→ r | (p→ q)/\(p→ r) |
0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 |
0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 |
0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 |
0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
1 | 0 | 1 | 0 | 0 | 0 | 1 | 0 |
1 | 1 | 0 | 0 | 0 | 1 | 0 | 0 |
1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
Hence they are logically equivalent.
Ans : ii)
P | Q | r | p\/q | (p\/q)→r | p→ r | q→ r | (p→ r)/\(q→ r) |
0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 |
0 | 0 | 1 | 0 | 1 | 1 | 1 | 1 |
0 | 1 | 0 | 1 | 0 | 1 | 0 | 0 |
0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 |
1 | 0 | 1 | 1 | 1 | 1 | 1 | 1 |
1 | 1 | 0 | 1 | 0 | 0 | 0 | 0 |
1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
Hence they are logically equivalent.
Ans : iii)
P | Q | r | q\/r | p→(q\/r) | p→ q | ¬r→(p→ q) |
0 | 0 | 0 | 0 | 1 | 1 | 1 |
0 | 0 | 1 | 1 | 1 | 1 | 1 |
0 | 1 | 0 | 1 | 1 | 1 | 1 |
0 | 1 | 1 | 1 | 1 | 1 | 1 |
1 | 0 | 0 | 0 | 0 | 0 | 0 |
1 | 0 | 1 | 1 | 1 | 0 | 1 |
1 | 1 | 0 | 1 | 1 | 1 | 1 |
1 | 1 | 1 | 1 | 1 | 1 | 1 |
Hence they are logically equivalent.
b). Use the substitution rules to show that
Ans : [p→ (q\/r)]<=> [(p/\¬q) → r]
[p→ (q\/r)] ó [¬r→ (p→ q)] From part (iii) of part (a)
ó [¬r→ (¬p\/q)] By the 2nd Substitution Rule,
And (p→ q)ó(¬p\/q)
ó [¬ (¬p\/q)→ ¬¬r] By the 1st Substitution Rule,
And (s→ t)ó (¬t → ¬s) for any
Primitive statement s, t
ó [(¬¬p/\¬q) → r] By De Morgan’s Law, Double Negation
ó [(p /\¬q) → r] By Double Negation and 2nd Substitution Rule
3. The following are three valid arguments. Establish the validity of each by means of a truth table.In each case, determine which rows of the table are crucial for assessing the validity of the argument and which rows can be ignored.
a) [p/\(p→ q)/\r]→[(p\/q)→r]
b) [[(p/\q)→r]/\¬q/\(p→¬r)]→(¬p\/¬q)
c) [[p\/(q\/r)/\¬q]→(p\/r)
Ans: a)
P | q | R | p→q | p\/q | (p\/q)→r |
0 | 0 | 0 | 1 | 0 | 1 |
0 | 0 | 1 | 1 | 0 | 1 |
0 | 1 | 0 | 1 | 1 | 0 |
0 | 1 | 1 | 1 | 1 | 1 |
1 | 0 | 0 | 0 | 1 | 0 |
1 | 0 | 1 | 0 | 1 | 1 |
1 | 1 | 0 | 1 | 1 | 0 |
1 | 1 | 1 | 1 | 1 | 1 |
The validity of the argument follows from the results in the last row.
Ans: b)
p | q | R | p/\q | (p/\q)→r | ¬q | ¬r | p→¬r | ¬p\/¬q |
0 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 |
0 | 0 | 1 | 0 | 1 | 1 | 0 | 1 | 1 |
0 | 1 | 0 | 0 | 1 | 0 | 1 | 1 | 1 |
0 | 1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 |
1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | 1 |
1 | 0 | 1 | 0 | 1 | 1 | 0 | 0 | 1 |
1 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 0 |
1 | 1 | 1 | 1 | 1 | 0 | 0 | 0 | 0 |
The validity of the argument follows the results in 1, 2, 5.
Ans: c)
p | Q | R | q\/r | p\/(q\/r) | ¬q | p\/r |
0 | 0 | 0 | 0 | 0 | 1 | 0 |
0 | 0 | 1 | 1 | 1 | 1 | 1 |
0 | 1 | 0 | 1 | 1 | 0 | 0 |
0 | 1 | 1 | 1 | 1 | 0 | 1 |
1 | 0 | 0 | 0 | 1 | 1 | 1 |
1 | 0 | 1 | 1 | 1 | 1 | 1 |
1 | 1 | 0 | 1 | 1 | 0 | 1 |
1 | 1 | 1 | 1 | 1 | 0 | 1 |
The results in rows 2,5,6 establish the validity of the given argument.
4) Which of the following sets are equal?
a) { 1,2,3 } b) { 3,2,1,3 }
c) {3,1,2,3 } d) {1,2,2,3}
Ans : As all the sets contains same elements ,therefore they are all same set.
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